MachineCalcs

Hydraulic Pump Flow & Power Calculator

Output flow from pump displacement and speed, plus the hydraulic power and the shaft (motor) power needed at your system pressure — with volumetric and overall efficiency. Metric and imperial. Free, no signup.

Hydraulics 5 inputs 3 results

Calculator

Volume pumped per revolution.
cm³
Drive speed of the pump shaft.
rpm
Working hydraulic pressure the pump runs against.
bar
Fraction of the geometric flow actually delivered (internal leakage loss).
Hydraulic power out ÷ shaft power in (volumetric × mechanical).

Results

Default result
Edit inputs
Output flow(Q)
24.84L/min

Geometric flow × volumetric efficiency.

Also computed

Hydraulic power6.624kW

Useful fluid power = Q × p.

Shaft power required7.793kW

Drive-motor input power.

Hydraulic power ÷ overall efficiency — size the drive motor to this.

Method notes 2 notes
  • Flow is geometric displacement × speed, reduced by the volumetric efficiency (internal leakage rises with pressure).
  • Hydraulic power uses the fluid-power shortcut kW = Q(L/min) × p(bar) ÷ 600; the shaft motor must supply that ÷ overall efficiency.

A hydraulic pump's output flow is its displacement times speed, reduced by volumetric efficiency: Q (L/min) = V(cm³/rev) · n(rpm) / 1000 · η_v. The hydraulic power follows the fluid-power shortcut kW = Q(L/min) · p(bar) / 600. This calculator also returns the shaft power your drive motor must supply, hydraulic power ÷ overall efficiency η_t, so you can size the motor.

Continue workflow

All Hydraulics

How to use this calculator

  1. Enter the displacement and speed. Enter the pump displacement (volume per revolution) and the drive speed in rpm.
  2. Enter the system pressure. Enter the working pressure the pump runs against.
  3. Enter the efficiencies. Enter the volumetric efficiency (sets the delivered flow) and the overall efficiency (sets the shaft power).
  4. Read flow and power. Read the output flow, the hydraulic power and the shaft power your drive motor must supply, in metric or imperial.

How it works

A positive-displacement pump moves a fixed volume each revolution, so its flow is simply displacement times speed, less internal leakage: Q = displacement · n · η_vol With displacement in cm³/rev and speed in rpm, dividing by 1000 gives litres per minute. The volumetric efficiency η_vol accounts for the flow that leaks back internally — it falls as pressure and wear rise.

The useful hydraulic power is flow against pressure. In practical units that reduces to the fluid-power shortcut P_hyd (kW) = Q (L/min) · p (bar) / 600 where the 600 constant carries the L/min·bar → kW conversion. The driving motor has to supply more than this, because the pump is not perfect: the shaft power is the hydraulic power divided by the overall efficiency, P_shaft = P_hyd / η_overall. Size the motor to the shaft power, not the hydraulic power.

Worked example

Verified against the live calculator

An 18 cm³/rev pump driven at 1500 rpm against 160 bar (16 MPa), with a volumetric efficiency of 92% and an overall efficiency of 85%. The flow is 18 × 1500 ÷ 1000 × 0.92 ≈ 24.8 L/min. The hydraulic power is 24.8 × 160 ÷ 600 ≈ 6.6 kW, so the shaft power required is ≈ 6.6 ÷ 0.85 = 7.8 kW (about 10.5 hp) — pick the next standard motor up. Load this page and the calculator shows these numbers.

Frequently asked questions

How do I calculate hydraulic pump flow from displacement and RPM?

Flow Q = displacement (cm³/rev) × speed (rpm) ÷ 1000 × volumetric efficiency, giving L/min. For example an 18 cm³/rev pump at 1500 rpm with 92% volumetric efficiency delivers 18 × 1500 ÷ 1000 × 0.92 ≈ 24.8 L/min. Enter the displacement, speed and efficiency above.

How do I calculate hydraulic power?

Use the fluid-power shortcut: power (kW) = flow (L/min) × pressure (bar) ÷ 600. So 24.8 L/min at 160 bar is 24.8 × 160 ÷ 600 ≈ 6.6 kW of hydraulic (useful) power. The 600 constant bakes in the L/min·bar → kW conversion.

What size motor do I need to drive the pump?

Size the motor to the shaft power = hydraulic power ÷ overall efficiency. At 6.6 kW hydraulic and 85% overall efficiency that is 6.6 ÷ 0.85 ≈ 7.8 kW (about 10.5 hp), so you would pick the next standard motor up.

What is volumetric efficiency?

It is the fraction of the geometric (theoretical) flow the pump actually delivers — the rest leaks internally past the clearances, and the loss grows with pressure and wear. Gear pumps are typically 0.85–0.93; piston pumps 0.92–0.97.

How do I get the flow in GPM?

Toggle Imperial in the header and the flow shows in US gallons per minute; the example above is about 6.6 GPM. Power switches to horsepower at the same time.

Does this work in metric and imperial?

Yes — toggle SI/Imperial in the header. Displacement switches between cm³ and in³, pressure between bar and psi, flow between L/min and GPM, and power between kW and hp.

Method & assumptions

  • Positive-displacement pump (gear, vane or piston) — flow is proportional to displacement and speed.
  • The 600 constant bakes in the L/min·bar → kW conversion for hydraulic power; it is exact, not an approximation.
  • Efficiencies are typical values — use the pump's own efficiency curves at your operating pressure for a firm number; both fall as pressure rises.
  • Ignores line and valve pressure losses, fluid compressibility and inlet (cavitation) limits; pressure is the working pressure at the pump outlet. Follow with the pump horsepower chart, hydraulic fluid velocity calculator and hose pressure-drop checks when sizing the lines fed by this pump flow.
Embed this calculator on your site free

Paste this where you want the calculator to appear. It stays in sync — same formulas, metric & imperial, light/dark — and a small credit link helps people find more tools.

Open widget

Live preview